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4b^2+21b+8=0
a = 4; b = 21; c = +8;
Δ = b2-4ac
Δ = 212-4·4·8
Δ = 313
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$b_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(21)-\sqrt{313}}{2*4}=\frac{-21-\sqrt{313}}{8} $$b_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(21)+\sqrt{313}}{2*4}=\frac{-21+\sqrt{313}}{8} $
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